The 22nd match of the IPL will be played in the PCA IS Bindra Stadium in Mohali, Chandigarh between KXIP and SRH. Both the teams are looking to get back on the winning wagon after suffering defeats at the hands of CSK and MI respectively.
The Sunrisers Hyderabad are badly plagued with a middle order that is one of the weakest in IPL 2019 with likes of Manish Pandey and Deepak Hooda showing their non-preparation against MI when SRH was bowled out for 96, their first score under 100 in their IPL history.
Given the importance of this match against KXIP, who are on the same six points as SRH, but on the sixth spot; SRH needs to bring out their A game against KXIP to defeat them.
This game will also see KXIP trying to forget their game against CSK. They were good against CSK, but much was left to be desired, as, despite KL Rahul and Sarfaraz Khan making half-centuries, KXIP lost the game by a margin of 22 runs chasing 160-odd.
Both the teams will be looking to gain two points and separate themselves from the middle of the pack in the points table.
Toss: Kings XI Punjab won the toss and elected to bowl first.
Playing XIs:
KXIP: Lokesh Rahul (w), Chris Gayle, Mayank Agarwal, Sarfaraz Khan, David Miller, Mandeep Singh, Sam Curran, Ravichandran Ashwin (c), Ankit Rajpoot, Mohammad Shami, Mujeeb Ur Rahman
SRH: David Warner, Jonny Bairstow (w), Vijay Shankar, Manish Pandey, Deepak Hooda, Yusuf Pathan, Mohammad Nabi, Rashid Khan, Bhuvneshwar Kumar (c), Siddharth Kaul, Sandeep Sharma.
